Simple Linear Interpolation Calculator

y = \frac{(X - X_1) \times (Y_2 - Y_1)}{(X_2 - X_1)} + Y_1\

Linear interpolation formula for estimating values between two known points

Result
Step by Step Solution
Data:
Formula for Interpolation:
\[y = \frac{(X - X_1) \times (Y_2 - Y_1)}{(X_2 - X_1)} + Y_1\]
Solution:

When I first discovered this online Linear Interpolation Calculator, I realized how powerful it is for solving problems that involve finding the coordinates of an arbitrary point lying on a straight line connecting two known points in a plane. You simply specify the x or y coordinate of interest, and by clicking the Calculate button, you can get the second coordinate as well as the interpolation parameters. This tool helps to find interpolated values between data points along a line or curve, and it plots the result visually. It also provides a step-by-step solution using the interpolation formula, making it easy to understand the context and gain a basic understanding of how to perform interpolation correctly.

This tool is a real time-saver. Whether you’re working with a given function or trying to calculate a value of y, it manages complex calculations faster than manual work. It presents detailed steps within fraction seconds, making it ideal for students and professionals alike. Once you get used to its standard terms and understand interpolation, you’ll appreciate how its simplicity meets precision. The Linear Interpolation Calculator truly transforms tedious math into an accessible step-by-step process that anyone can follow confidently.


When you imagine trying to measure the dependence between the amount of flour you bake cookies with and the number of cookies you get, it becomes clear how linear interpolation works. The first time, I used 200 g of flour and got 15 cookies, and the second time I used 300 g and got 20 cookies. Now, to know how many cookies I’d get if I used 250 g, I’d assume a relationship that’s linear relationship. What I’m looking for is interpolation, a method for creating new data points from an already known discrete set of information. If I went beyond the tested range, like 500 g, that would be called extrapolation instead.

In mathematics, this procedure helps you produce a simple function that stays close to the original data by integration of a new value between known ones, a process known as interpolation. In other words, we can say the interpolant is a straight line that exists between two recognized coordinates, like (x0, y0) and (x1, y1). You can readily find the coordinates using an interpolation calculator, which applies a mathematical process for finding any unknown value by using already-known values. This makes it useful for determining specific variables where data falls between known points, forming a linear function or curve that connects them.

According to Wikipedia, it is defined as a fitting technique that uses a polynomial to construct a curve graphically represented by a figure or formula. This helps to estimate intermediate values, especially for applications like forecasting, predictive results, the stock market, and financial modeling. This technique, assuming a constant rate of change, makes linear interpolation the best for constructing data between two known values. It’s considered a simple form of curve fitting, where the line itself represents the relationship perfectly within a series of data points.

How Does The Linear Interpolation Calculator Work?

The Linear Interpolation Calculator is a mathematical tool that helps estimate unknown values between two known data points on a straight line. In simple terms, if you know two points on a graph and want to find a value that lies between them (or even slightly beyond), this calculator gives you the precise result using a standard interpolation formula.

It’s commonly used in engineering, physics, finance, and data analysis, where it’s important to estimate values that aren’t directly measured, such as temperature, pressure, or performance values between two data points.

The Formula Used

The calculator uses the linear interpolation formula:

Y = (X2​−X1​) × (Y2​−Y1​) / (X−X1​) ​+ Y1​

Where:

  • X₁, Y₁ = first known point
  • X₂, Y₂ = second known point
  • X = the x-value for which you want to find the corresponding y-value
  • Y = the estimated y-value (result)

This formula assumes a linear relationship between the two points — meaning that the rate of change between them is constant.

Step 1: Write the Formula

Y = (X2​−X1​) × (Y2​−Y1​) / (X−X1​) ​+ Y1​

Step 2: Substitute the Values

Y = (14−12) × (4−11) / (3−12) + 11 

Step 3: Simplify the Terms

  • (14−12) = 2
  • (4−11) = −7
  • (3−12) = −9

Now substitute these values: Y = 2 × (−7) ​/ −9 + 11

Step 4: Multiply and Divide

  • Y = −14 / −9 ​+11 
  • Y = 1.5555556 + 11

Step 5: Final Result

Y = 12.555556

The calculator shows that when X = 14, the estimated Y value is 12.555556.

This means that based on the straight-line relationship between the given data points (X₁=12, Y₁=11 and X₂=3, Y₂=4), the point at X=14 would fall at approximately Y=12.56 on the same line.

Even though 14 is slightly outside the known range (since our data points are between 3 and 12), the calculator still applies the same formula. This process is called linear extrapolation, which extends the line beyond the given points.

Different Types of Interpolation Methods

Polynomial Interpolation

As the name suggests, this method uses polynomials of higher degrees to find unknown data that shows a non-linear trend. I often imagine it like a car accelerating from a stoplight; in that instance, the speed keeps changing, and the distance has a non-linear relationship with time. In such cases, polynomial interpolation works better than linear methods because it can calculate the given values more precisely, creating a smooth image of how the data behaves between known points.

Spline Interpolation

The spline interpolation technique connects data points using a series of low-degree polynomials instead of a single linear or polynomial curve. From my experience working with graphs, this method provides a smooth and stable image that is better suited for large sets of data, making the process more efficient. By using these small, flexible curves, spline interpolation can represent complex patterns without the wild swings that higher-degree equations sometimes create.

Nearest Neighbor Interpolation

The nearest neighbor interpolation type is the simplest and fastest method when compared to other methods, which makes it highly suitable for real-time applications or scenarios with limited processing power. In this method, the value of an unknown data point is assigned to the known data point that is closest to it. From my experience working with discrete sets in image editing, this interpolation approach works best for maintaining pixel sharpness, especially when resizing an image quickly without complex computation.

Logarithmic Interpolation

The logarithmic interpolation type is a specialized method used for specific data sets that follow a trend where values change logarithmically rather than linearly. From my experience in analyzing growth models, this interpolation method captures the real meaning of gradual or exponential variations, making it ideal for data such as sound intensity or population growth that doesn’t increase at a constant rate.

Newton Interpolation

The Newton interpolation method is a smart way of constructing a polynomial that passes through a given set of data points. Its basic concept relies on divided differences and uses a recursive approach to calculate coefficients efficiently, producing stable results even when working with unevenly spaced points. From my own work in numerical modeling, I’ve found this method ideal for small to medium data sets, as it offers high accuracy without becoming overly complex.

Lagrange Interpolation

The Lagrange interpolation is a numerical method used to approximate a function that passes through a given set of points. The difference, unlike linear interpolation, is that it fits a polynomial of degree n-1, where n is the number of data points. This unique feature makes it better suited for handling complex datasets, especially when smooth curves are required. From my personal experience, the Lagrange interpolation offers precise control over data behavior, which is quite useful in analytical and modeling tasks.

FAQs

Why is interpolation used?

In the real world, data is often incomplete or collected at discrete points, which makes interpolation a vital process. It is used in many different fields to estimate the exact value between a set of known values. From my own experience working with graphs and measurements, I’ve seen how this essential tool supports analysis and prediction, allowing us to fill in missing information and make accurate assumptions where direct data is unavailable.

How accurate is interpolation?

The accuracy of interpolation largely depends on how clean and consistent your data set is. When the data is free from noise and follows a real trend, the resulting estimates usually have fewer errors and are more reliable. However, in my experience working with measurement datasets, if the points are scattered or contain lots of anomalous values, the results can still vary, proving that clean data always improves precision and reliability.

Why is interpolation called linear interpolation?

The process of finding an interpolated value relies on the use of a linear polynomial function with a degree 1 equation. This means the relationship between the points forms a straight line, which I’ve often found to be the simplest yet most effective way to estimate unknown data. Due to this linear behavior, the method is called linear interpolation, as it connects two known points with precision using just a first-degree function.

How to perform the interpolation on a set of values?

First, note all data values carefully before you start the calculation. Then, put those numbers into the linear interpolation formula and simplify it step by step to get the required interpolated value. In my experience, to match the results accurately, it’s best to use an online calculator, just enter the given inputs, and you’ll instantly find the precise interpolated value without any manual errors.

Table Of Content
Scroll to Top